Ex 11.3, 11 - Chapter 11 Class 11 Conic Sections (Term 2)
Last updated at Feb. 6, 2020 by Teachoo
Last updated at Feb. 6, 2020 by Teachoo
Transcript
Ex 11.3, 11 Find the equation for the ellipse that satisfies the given conditions: Vertices (0, ยฑ13), foci (0, ยฑ5) Given Vertices (0, ยฑ13) Hence The vertices are of the form (0, ยฑa) Hence, the major axis is along y-axis & Equation of ellipse is of the form ๐^๐/๐^๐ + ๐^๐/๐^๐ = 1 From (1) & (2) a = 13 Also given coordinate of foci = (0, ยฑ5) We know that foci are = (0, ยฑc) So c = 5 We know that c2 = a2 โ b2 (5) 2 = (13) 2 โ b2 b2 = (13) 2 โ (5) 2 b2 = 169 โ 25 b2 = 144 Equation of ellipse is ๐ฅ^2/๐^2 + ๐ฆ^2/๐^2 = 1 Putting value ๐^๐/๐๐๐ + ๐^๐/๐๐๐ = 1 Equation of ellipse is ๐ฅ^2/๐^2 + ๐ฆ^2/๐^2 = 1 Putting value ๐^๐/๐๐๐ + ๐^๐/๐๐๐ = 1
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